Datasheet S-19213 (ABLIC) - 10

AUTOMOTIVE, 125°C OPERATION, 36 V INPUT, 500 mA VOLTAGE REGULATOR S-19213 Series
Rev.1.1_00
2. Type in which output voltage is externally set Table 10
(Tj = −40°C to +125°C, VOUT = VVADJ unless otherwise specified) Test Item Symbol Condition Min. Typ. Max. Unit Circuit Adjustment pin V V IN = 13.5 V, IOUT = 10 mA 1.773 1.8 1.827 V 7 output voltage
*1
VADJ 2.8 V ≤ VIN ≤ 18.0 V, 1 mA ≤ IOUT ≤ 200 mA 1.768 1.8 1.832 V 7 Output voltage range VROUT − 1.8 − 30.0 V 13 Adjustment pin internal R resistance VADJ − − 26 − MΩ − Output current
*2
IOUT 2.8 V ≤ VIN 500
*4
− − mA 9 Dropout voltage
*3
Vdrop IOUT = 200 mA, Ta = +25°C −
*5
− V 7 ΔV Line regulation OUT1 Δ V 2.8 V ≤ VIN ≤ 28.0 V, IOUT = 10 mA − 0.015 0.03 %/V 7 IN • VOUT V Load regulation ΔV IN = 2.8 V, OUT2 − 15 30 mV 7 1 mA ≤ IOUT ≤ 200 mA, Ta = +25°C Current consumption I during operation SS1 VIN = 13.5 V, ON / OFF pin = ON, IOUT = 10 μA − 5.0 9.8 μA 8 Current consumption I during power-off SS2 VIN = 13.5 V, ON / OFF pin = OFF, no load − 0.1 2.0 μA 8 Input voltage VIN − 2.8 − 36.0 V − ON / OFF pin V V IN = 13.5 V, RL = 1.0 kΩ, input voltage "H" SH determined by VOUT output level 2.0 − − V 10 ON / OFF pin V V IN = 13.5 V, RL = 1.0 kΩ, input voltage "L" SL determined by VOUT output level − − 0.8 V 10 ON / OFF pin I input current "H" SH VIN = 13.5 V, VON / OFF = VIN −0.1 0.3 1.0 μA 10 ON / OFF pin I input current "L" SL VIN = 13.5 V, VON / OFF = 0 V −0.1 − 0.1 μA 10 V Ripple rejection |RR| IN = 13.5 V, f = 100 Hz, ΔVrip = 0.5 Vrms, − 60 − dB 11 IOUT = 100 mA, Ta = +25°C V Short-circuit current I IN = 2.8 V, ON / OFF pin = ON, short − 150 − mA 9 VOUT = 0 V, Ta = +25°C Thermal shutdown T detection temperature SD Junction temperature − 170 − °C − Thermal shutdown T release temperature SR Junction temperature − 135 − °C − Discharge shunt V resistance during R IN = 13.5 V, ON / OFF pin = OFF, LOW − 3.0 − kΩ 12 V power-off OUT = 0.1 V
*1.
VOUT(S): Set output voltage = 1.8 V
*2.
The output current at which the output voltage becomes 95% of VOUT(E) after gradually increasing the output current.
*3.
Vdrop = VIN1 − (VOUT3 × 0.98) VIN1 is the input voltage at which the output voltage becomes 98% of VOUT3 after gradually decreasing the input voltage. VOUT3 is the output voltage when VIN = VOUT(S) + 1.0 V and IOUT = 200 mA.
*4.
Due to limitation of the power dissipation, this value may not be satisfied. Attention should be paid to the power dissipation when the output current is large. This specification is guaranteed by design.
*5.
The dropout voltage is limited by the difference between the input voltage (min. value) and the set output voltage. In case of 1.8 V ≤ VOUT(S) < 2.8 V: 2.8 V − VOUT(S) = Vdrop 10